Обсуждение: Re: JDBC: Exception when calling ResultSet.previous()

Peter Wasem schreef:
>In a JAVA-project I need to process a ResultSet with both methods
>previous() and next() to move
>arround in ResultSets. The ResultSet method next() is no problem. But
>when I call the next()
>method I get the following exception.
> 
>Exception in thread "main" java.lang.AbstractMethodError:
>org/postgresql/jdbc1/ResultSet.previous

It seems you're using a PostgreSQL driver built for JDBC-1, whereas
ResultSet.previous() is new in JDBC-2. Try jdbc7.1-1.3.jar from
http://jdbc.fastcrypt.com/

FYI there is a mailing list about PostgreSQL/JDBC. See
http://www.ca.postgresql.org/users-lounge/

-- 
René Pijlman <rpijlman@spamcop.net>

Rene Pijlman wrote:
>
> Peter Wasem schreef:
> >In a JAVA-project I need to process a ResultSet with both methods
> >previous() and next() to move
> >arround in ResultSets. The ResultSet method next() is no problem. But
> >when I call the next()
> >method I get the following exception.
> >
> >Exception in thread "main" java.lang.AbstractMethodError:
> >org/postgresql/jdbc1/ResultSet.previous
>
> It seems you're using a PostgreSQL driver built for JDBC-1, whereas
> ResultSet.previous() is new in JDBC-2. Try jdbc7.1-1.3.jar from
> http://jdbc.fastcrypt.com/
>
> FYI there is a mailing list about PostgreSQL/JDBC. See
> http://www.ca.postgresql.org/users-lounge/
>
> --
> René Pijlman <rpijlman@spamcop.net>

Hi René

Sorry but I was very busy the last few weeks.
That was exaclty the solution to the problem.

Thanks!