Re: Function Help

>>>>> "Brian" == Brian C Doyle <bcdoyle@mindspring.com> writes:

Brian> Hello all,
Brian> I am working on a function to determine the date of the first saturday
Brian> of the month.

Brian> Currently I have:

Brian> CREATE FUNCTION first_saturday(date)
Brian> RETURNS date
Brian> AS '
Brian> Select CASE WHEN date_part(\'dow\',\'$1\'::DATE)=0 THEN date(\'$1\')+6
Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=1 THEN date(\'$1\')+5
Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=2 THEN date(\'$1\')+4
Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=3 THEN date(\'$1\')+3
Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=4 THEN date(\'$1\')+2
Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=5 THEN date(\'$1\')+1
Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=6 THEN date(\'$1\')+0
Brian> END'LANGUAGE 'sql'

Brian> I get an error that $1 is not a valid date.  But I want that to be the
Brian> variable I enter...
Brian> what Am I doing wrong???

Working too hard? :)

why not just:

My_Col + 6 - date_part('dow', My_Col)

Don't even need a function for that. :)

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