Re: Function Help
От | Brian C. Doyle |
---|---|
Тема | Re: Function Help |
Дата | |
Msg-id | 5.0.2.1.0.20010924202954.009f76d0@pop.mindspring.com обсуждение исходный текст |
Ответ на | Re: Function Help (merlyn@stonehenge.com (Randal L. Schwartz)) |
Список | pgsql-general |
The main reason is that I am not quering a table with it as of yet... Ultimately it will before query that is a Month do date query that does not use a calender month At 05:29 PM 9/24/01 -0700, Randal L. Schwartz wrote: > >>>>> "Brian" == Brian C Doyle <bcdoyle@mindspring.com> writes: > >Brian> Hello all, >Brian> I am working on a function to determine the date of the first saturday >Brian> of the month. > >Brian> Currently I have: > >Brian> CREATE FUNCTION first_saturday(date) >Brian> RETURNS date >Brian> AS ' >Brian> Select CASE WHEN date_part(\'dow\',\'$1\'::DATE)=0 THEN date(\'$1\')+6 >Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=1 THEN date(\'$1\')+5 >Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=2 THEN date(\'$1\')+4 >Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=3 THEN date(\'$1\')+3 >Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=4 THEN date(\'$1\')+2 >Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=5 THEN date(\'$1\')+1 >Brian> WHEN date_part(\'dow\',\'$1\'::DATE)=6 THEN date(\'$1\')+0 >Brian> END'LANGUAGE 'sql' > >Brian> I get an error that $1 is not a valid date. But I want that to be the >Brian> variable I enter... >Brian> what Am I doing wrong??? > >Working too hard? :) > >why not just: > >My_Col + 6 - date_part('dow', My_Col) > >Don't even need a function for that. :) > >-- >Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095 ><merlyn@stonehenge.com> <URL:http://www.stonehenge.com/merlyn/> >Perl/Unix/security consulting, Technical writing, Comedy, etc. etc. >See PerlTraining.Stonehenge.com for onsite and open-enrollment Perl training!
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