Re: plperl syntax question
От | Rob Sargent |
---|---|
Тема | Re: plperl syntax question |
Дата | |
Msg-id | F7492779-7336-4E58-92C8-35C7C44FB7C5@gmail.com обсуждение исходный текст |
Ответ на | Re: plperl syntax question (stan <stanb@panix.com>) |
Ответы |
Re: plperl syntax question
Re: plperl syntax question |
Список | pgsql-general |
You can see that the entire sql string is quoted, where what you want from the elog is just single quotes around the value (i.e. 'stan’)On Mar 12, 2020, at 7:44 PM, stan <stanb@panix.com> wrote:On Thu, Mar 12, 2020 at 06:37:02PM -0700, David G. Johnston wrote:On Thursday, March 12, 2020, stan <stanb@panix.com> wrote:
my $rv3 = spi_exec_query('$stmt');
What am I doing wrong here?
Putting a variable name into a single-quoted string and expecting it to
resolve to the contents of said variable instead of being treated as a
literal.
David J.
Please look at this.
Here is the code:
my $stmt = qq('SELECT employee_key from employee where id = $user ;');
elog( NOTICE, "stmt = $stmt" );
my $rv3 = spi_exec_query($stmt);
As you cna see, I use qq to ahndle the qouting: runtime output looks like
this:
OTICE: stmt = 'SELECT employee_key from employee where id = stan ;’
The example I saw for qq on the perl site
doesn’t have any quotes in arg to qq(
qq(Welcome to GeeksForGeeks)
);
Try making the sql string without using qq
my $select = “select....’” + $user + “‘;”;
(or perhaps perl has a formatted string function like printf)
ERROR: syntax error at or near "$" at line 22.
Looks like a very clean string with the variable substituted.
Anyone have a working example of a call to spi_exec_query() using a variable?
also tried:
my $rv3 = spi_exec_query('$stmt');
Different trun tiem error message.
--
"They that would give up essential liberty for temporary safety deserve
neither liberty nor safety."
-- Benjamin Franklin
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