Re: plperl syntax question
От | David G. Johnston |
---|---|
Тема | Re: plperl syntax question |
Дата | |
Msg-id | CAKFQuwZa_k+7ZMrwksb+TGE9dP-mo1J9W1VHz7dSimA8cBFNEA@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: plperl syntax question (Rob Sargent <robjsargent@gmail.com>) |
Список | pgsql-general |
On Thursday, March 12, 2020, Rob Sargent <robjsargent@gmail.com> wrote:
On Mar 12, 2020, at 7:44 PM, stan <stanb@panix.com> wrote:On Thu, Mar 12, 2020 at 06:37:02PM -0700, David G. Johnston wrote:On Thursday, March 12, 2020, stan <stanb@panix.com> wrote:
my $rv3 = spi_exec_query('$stmt');
What am I doing wrong here?
Putting a variable name into a single-quoted string and expecting it to
resolve to the contents of said variable instead of being treated as a
literal.
David J.
Please look at this.
Here is the code:
my $stmt = qq('SELECT employee_key from employee where id = $user ;');
elog( NOTICE, "stmt = $stmt" );
my $rv3 = spi_exec_query($stmt);
So you fixed the error in the third line i and others pointed out but then decided to introduce a new error by changing the first line...
David J.
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