Re: Why doesn't update syntax match insert syntax?
От | Merlin Moncure |
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Тема | Re: Why doesn't update syntax match insert syntax? |
Дата | |
Msg-id | CAHyXU0wkYhtz8jst-3-eX3wHHBtG9fioR0jdH0nxmvoCi9kRYg@mail.gmail.com обсуждение исходный текст |
Ответ на | Why doesn't update syntax match insert syntax? (Rob Richardson <RDRichardson@rad-con.com>) |
Ответы |
Re: Why doesn't update syntax match insert syntax?
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Список | pgsql-general |
On Thu, Oct 10, 2013 at 10:03 AM, Rob Richardson <RDRichardson@rad-con.com> wrote: > I've been curious about this for a long time. The syntax for an INSERT query is often much easier to use, in my opinion,then the syntax for an UPDATE query. For example, and this is what I am trying to do, assume you have a table ofinner covers containing a name field and fields named x and y to track where each cover is, and you have another tableof permissible locations for inner covers and other things, with fields containing the name of the stored item, itstype, and its x and y coordinates. > > I am resetting my database to initial conditions, so I am putting the inner covers in their storage locations. I've alreadyupdated the storage location table, and now I want to update the locations in the inner cover table. So I want todo this: > > UPDATE inner_covers (X, Y) > SELECT sl.X, sl.Y FROM storage_locations sl where sl.name = inner_covers.name > > If I were doing an insertion, that syntax would work. But instead, I'm forced to do this: > > UPDATE inner_covers > SET X = (SELECT sl.X FROM storage_locations sl where sl.name = inner_covers.name), > Y = (SELECT sl.Y FROM storage_locations sl where sl.name = inner_covers.name) > > Or is there another, more convenient form of the UPDATE query that I'm not familiar with? > > Thanks very much! you have UPDATE FROM: UPDATE foo SET a=bar.a, b=bar.b FROM bar WHERE foo.id = bar.id; merlin
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