Re: replacing expresion in plpgsql
От | Juan Pablo L |
---|---|
Тема | Re: replacing expresion in plpgsql |
Дата | |
Msg-id | CABSYDaby9-x3M2Xvd7NDHPGAO6x1t0w7K6Uc6ZwM6ejROi5K4A@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: replacing expresion in plpgsql (Andreas Brandl <ml@3.141592654.de>) |
Список | pgsql-general |
Hi i m working with timestamp cause i need the time too. i tried your solution and it works perfectly, it just does not adjust to my problem. thanks a lot for the answer.
On 15 December 2013 18:17, Andreas Brandl <ml@3.141592654.de> wrote:
Hi,
----- Ursprüngliche Mail -----
>
> Hi, i have a function that receives a parameter which represents
> days:
>
>
> FUNCTION aaa_recharge_account(expdays integer)
>
>
> i want to add those days to the CURRENT_DATE, but i do not know how
> to do it, i have tried several ways to replace that in an expresion
> like:
assuming you want to add expdays days to the CURRENT_DATE, you can just use + arithmetic of date:
# SELECT CURRENT_DATE + 5 as in_the_future_after_5_days;
in_the_future_after_5_days
----------------------------
2013-12-21
(1 row)
>
> newexpdate := CURRENT_TIMESTAMP + interval '$1 days' using expdays;
> (newexpdate is declared as timestamp)
>
>
> and many more but none work, can someone please help me to find out
> how can i replace that parameter into an expression that i can add
> to CURRENT_TIMESTAMP or any other way that i can accomplish what i
> need which is to add that parameter to the current timestamp.
> thanks!!!
Check this out:
# select current_timestamp, current_timestamp + interval '2' day;
now | ?column?
-------------------------------+-------------------------------
2013-12-16 01:16:19.783235+01 | 2013-12-18 01:16:19.783235+01
(1 row)
AFAIK that should also be SQL compliant.
Regards,
Andreas
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