Re: replacing expresion in plpgsql
От | Andreas Brandl |
---|---|
Тема | Re: replacing expresion in plpgsql |
Дата | |
Msg-id | 2fbfc057-74c8-4fa6-a988-c3b52c5da44b@store1.zcs.ext.wpsrv.net обсуждение исходный текст |
Ответ на | replacing expresion in plpgsql (Juan Pablo L <jpablolorenzetti@gmail.com>) |
Ответы |
Re: replacing expresion in plpgsql
Re: replacing expresion in plpgsql |
Список | pgsql-general |
Hi, ----- Ursprüngliche Mail ----- > > Hi, i have a function that receives a parameter which represents > days: > > > FUNCTION aaa_recharge_account(expdays integer) > > > i want to add those days to the CURRENT_DATE, but i do not know how > to do it, i have tried several ways to replace that in an expresion > like: assuming you want to add expdays days to the CURRENT_DATE, you can just use + arithmetic of date: # SELECT CURRENT_DATE + 5 as in_the_future_after_5_days; in_the_future_after_5_days ---------------------------- 2013-12-21 (1 row) > > newexpdate := CURRENT_TIMESTAMP + interval '$1 days' using expdays; > (newexpdate is declared as timestamp) > > > and many more but none work, can someone please help me to find out > how can i replace that parameter into an expression that i can add > to CURRENT_TIMESTAMP or any other way that i can accomplish what i > need which is to add that parameter to the current timestamp. > thanks!!! Check this out: # select current_timestamp, current_timestamp + interval '2' day; now | ?column? -------------------------------+------------------------------- 2013-12-16 01:16:19.783235+01 | 2013-12-18 01:16:19.783235+01 (1 row) AFAIK that should also be SQL compliant. Regards, Andreas
В списке pgsql-general по дате отправления: