Re: Query, view join question.
От | vhikida@inreach.com |
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Тема | Re: Query, view join question. |
Дата | |
Msg-id | 59009.146.74.1.99.1105040872.squirrel@146.74.1.99 обсуждение исходный текст |
Ответ на | Re: Query, view join question. (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-general |
I think there is an echo in here :) It's probably me. I pass for the rest of this thread. > "Joost Kraaijeveld" <J.Kraaijeveld@Askesis.nl> writes: >> CREATE OR REPLACE VIEW even AS >> SELECT DISTINCT abo_his.klantnummer, >>> abo_his.artikelnummer, abo_his.code_retour, >>> abo_klt.aantal_abonnementen, abo_klt.afgewerkt >> FROM abo_his >> JOIN abo_klt ON abo_his.klantnummer = abo_klt.klantnummer >> WHERE abo_his.abonnement = 238 >> ORDER BY abo_his.klantnummer, abo_his.artikelnummer, >>> abo_his.code_retour, abo_klt.aantal_abonnementen, abo_klt.afgewerkt; > >> In the table abo_klt there is no record where abo_klt.abonnement = 238 >> and abo_klt.afgewerkt > 0: > >> munt=# select * from abo_klt where abonnement = 238 and afgewerkt > 0; > > Yes, but the join isn't testing abo_klt.abonnement. It's testing > abo_his.abonnement. If there's a reason to think that rows in the two > tables with the same klantnummer must also have the same abonnement, > you have not said what it is. > > regards, tom lane > > ---------------------------(end of broadcast)--------------------------- > TIP 8: explain analyze is your friend >
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