Re: Query, view join question.
От | Tom Lane |
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Тема | Re: Query, view join question. |
Дата | |
Msg-id | 19054.1105040076@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: Query, view join question. ("Joost Kraaijeveld" <J.Kraaijeveld@Askesis.nl>) |
Ответы |
Re: Query, view join question.
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Список | pgsql-general |
"Joost Kraaijeveld" <J.Kraaijeveld@Askesis.nl> writes: > CREATE OR REPLACE VIEW even AS > SELECT DISTINCT abo_his.klantnummer, >> abo_his.artikelnummer, abo_his.code_retour, >> abo_klt.aantal_abonnementen, abo_klt.afgewerkt > FROM abo_his > JOIN abo_klt ON abo_his.klantnummer = abo_klt.klantnummer > WHERE abo_his.abonnement = 238 > ORDER BY abo_his.klantnummer, abo_his.artikelnummer, >> abo_his.code_retour, abo_klt.aantal_abonnementen, abo_klt.afgewerkt; > In the table abo_klt there is no record where abo_klt.abonnement = 238 and abo_klt.afgewerkt > 0: > munt=# select * from abo_klt where abonnement = 238 and afgewerkt > 0; Yes, but the join isn't testing abo_klt.abonnement. It's testing abo_his.abonnement. If there's a reason to think that rows in the two tables with the same klantnummer must also have the same abonnement, you have not said what it is. regards, tom lane
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