Re: createuser --memeber and PG 16
От | Tom Lane |
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Тема | Re: createuser --memeber and PG 16 |
Дата | |
Msg-id | 264838.1684683924@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: createuser --memeber and PG 16 (Bruce Momjian <bruce@momjian.us>) |
Ответы |
Re: createuser --memeber and PG 16
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Список | pgsql-hackers |
Bruce Momjian <bruce@momjian.us> writes: > On Sun, May 21, 2023 at 08:22:05AM -0700, Nathan Bossart wrote: >> I've attached a draft patch for this. I also changed --admin to >> --with-admin. > If we want to go forward with this, the big question is whether we want > to get this in before beta1. FYI, the release notes don't mention the > option names. +1 for doing it before beta1. A few comments on the patch: >> Indicates an existing role that will be automatically added as a member of the new "Specifies" would be clearer than "indicates" (not your fault, but let's avoid the passive construction while we are here). Likewise nearby. >> + {"member-of", required_argument, NULL, 6}, Why didn't you just translate this as 'g' instead of inventing a new switch case? >> - printf(_(" -a, --admin=ROLE this role will be a member of new role with admin\n" >> + printf(_(" -a, --with-admin=ROLE this role will be a member of new role with admin\n" I think clearer would be >> + printf(_(" -a, --with-admin=ROLE ROLE will be a member of new role with admin\n" Likewise >> + printf(_(" -g, --member-of=ROLE new role will be a member of ROLE\n")); (I assume that's what this should say, it's backwards ATM) and >> + printf(_(" -m, --with-member=ROLE ROLE will be a member of new role\n")); regards, tom lane
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