Re: createuser --memeber and PG 16

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От Nathan Bossart
Тема Re: createuser --memeber and PG 16
Дата
Msg-id 20230521170756.GA4034216@nathanxps13
обсуждение исходный текст
Ответ на Re: createuser --memeber and PG 16  (Tom Lane <tgl@sss.pgh.pa.us>)
Ответы Re: createuser --memeber and PG 16  (Tom Lane <tgl@sss.pgh.pa.us>)
Re: createuser --memeber and PG 16  (Peter Eisentraut <peter.eisentraut@enterprisedb.com>)
Список pgsql-hackers
On Sun, May 21, 2023 at 11:45:24AM -0400, Tom Lane wrote:
> A few comments on the patch:

Thanks for taking a look.

>>>          Indicates an existing role that will be automatically added as a member of the new
> 
> "Specifies" would be clearer than "indicates" (not your fault, but
> let's avoid the passive construction while we are here).  Likewise
> nearby.

Fixed.

>>> +        {"member-of", required_argument, NULL, 6},
> 
> Why didn't you just translate this as 'g' instead of inventing
> a new switch case?

Fixed.  *facepalm*

> I think clearer would be
> 
>>> +    printf(_("  -a, --with-admin=ROLE     ROLE will be a member of new role with admin\n"
> 
> Likewise
> 
>>> +    printf(_("  -g, --member-of=ROLE      new role will be a member of ROLE\n"));
> 
> (I assume that's what this should say, it's backwards ATM)
> and
> 
>>> +    printf(_("  -m, --with-member=ROLE    ROLE will be a member of new role\n"));

Fixed.

How do folks feel about keeping --role undocumented?  Should we give it a
mention in the docs for --member-of?

-- 
Nathan Bossart
Amazon Web Services: https://aws.amazon.com

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