Re: inverse of "day of year"
От | Tom Lane |
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Тема | Re: inverse of "day of year" |
Дата | |
Msg-id | 24189.1079709005@sss.pgh.pa.us обсуждение исходный текст |
Ответ на | Re: inverse of "day of year" (Robert Creager <Robert_Creager@LogicalChaos.org>) |
Ответы |
Re: inverse of "day of year"
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Список | pgsql-sql |
Robert Creager <Robert_Creager@LogicalChaos.org> writes: > Martin Marques <martin@bugs.unl.edu.ar> confessed: >> Is there a function that would give me the date for a given day of year? > Something like: > select date_trunc( 'year', now() ) + (extract( doy from now() ) - 1) * > '1day'::interval; timestamp + interval arithmetic is likely to give you problems at daylight savings boundaries, since '1day' will be taken as '24hours'. A more reliable way to get (what I assume is) the desired result is to use the date + integer operator: select date_trunc('year', now())::date + (extract(doy from now()) - 1)::integer; regards, tom lane
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