Re: inverse of "day of year"
От | Martin Marques |
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Тема | Re: inverse of "day of year" |
Дата | |
Msg-id | 200403220832.32968.martin@bugs.unl.edu.ar обсуждение исходный текст |
Ответ на | Re: inverse of "day of year" (Tom Lane <tgl@sss.pgh.pa.us>) |
Ответы |
Re: inverse of "day of year"
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Список | pgsql-sql |
El Vie 19 Mar 2004 12:10, Tom Lane escribió: > Robert Creager <Robert_Creager@LogicalChaos.org> writes: > > Martin Marques <martin@bugs.unl.edu.ar> confessed: > >> Is there a function that would give me the date for a given day of year? > > > > Something like: > > > > select date_trunc( 'year', now() ) + (extract( doy from now() ) - 1) * > > '1day'::interval; > > timestamp + interval arithmetic is likely to give you problems at > daylight savings boundaries, since '1day' will be taken as '24hours'. Is there information on how other intervals are taken? I mean, how is '1 year' afected with the leap years? -- 08:30:01 up 13 days, 13:01, 3 users, load average: 2.04, 1.80, 1.04 ----------------------------------------------------------------- Martín Marqués | select 'mmarques' || '@' || 'unl.edu.ar' Centro de Telematica | DBA, Programador, Administrador Universidad Nacional del Litoral -----------------------------------------------------------------
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