Re: pg_ctl idempotent option
От | Bruce Momjian |
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Тема | Re: pg_ctl idempotent option |
Дата | |
Msg-id | 20130115192856.GE27934@momjian.us обсуждение исходный текст |
Ответ на | Re: pg_ctl idempotent option (Tom Lane <tgl@sss.pgh.pa.us>) |
Ответы |
Re: pg_ctl idempotent option
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Список | pgsql-hackers |
On Tue, Jan 15, 2013 at 10:25:23AM -0500, Tom Lane wrote: > Alvaro Herrera <alvherre@2ndquadrant.com> writes: > > Vik Reykja escribi�: > >> On Mon, Jan 14, 2013 at 4:22 PM, Tom Lane <tgl@sss.pgh.pa.us> wrote: > >>> Idempotent is a ten-dollar word. Can we find something that average > >>> people wouldn't need to consult a dictionary to understand? > > >> I disagree that we should dumb things down when the word means exactly what > >> we want and based on the rest of this thread is the only word or word > >> cluster that carries the desired meaning. > > I'm not quite convinced that it means *exactly* what we want. The > dictionary definition, according to my laptop's dictionary, is "denoting > an element of a set that is unchanged in value when multiplied or > otherwise operated on by itself". I'm well aware that computer people > often use it to mean "an operation that doesn't change the system state > if the state is already what's wanted", but I think that's probably an > abuse of the mathematical usage. And in any case, I'm not sure that > non-hackers would immediately recognize the term, nor be enlightened by > their dictionaries. But ... I have heard idempotent used several times by our folks, and I didn't know what it meant either. I figured it was a "strong item". ;-) I just looked it up. -- Bruce Momjian <bruce@momjian.us> http://momjian.us EnterpriseDB http://enterprisedb.com + It's impossible for everything to be true. +
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