Re: subquery/alias question
От | Alvaro Herrera |
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Тема | Re: subquery/alias question |
Дата | |
Msg-id | 20070925223048.GN6440@alvh.no-ip.org обсуждение исходный текст |
Ответ на | Re: subquery/alias question (Michael Glaesemann <grzm@seespotcode.net>) |
Ответы |
Re: subquery/alias question
|
Список | pgsql-general |
Michael Glaesemann wrote: > > On Sep 25, 2007, at 16:59 , Madison Kelly wrote: > >> SELECT >> d.dom_id, >> d.dom_name, >> (SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id) >> AS >> usr_count >> FROM >> domains d >> WHERE >> (SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id) > 0 >> ORDER BY d.dom_name ASC; > > Why not just use a join? Something like this would work, I should think: > > select dom_id, > dom_name, > usr_count > from domains > natural join (select usr_dom_id as dom_id, > count(usr_dom_id) as usr_count > from users) u > where usr_count > 0 > order by dom_name; Maybe the usr_count should be tested in a HAVING clause instead of WHERE? And put the count(*) in the result list instead of a subselect. That feels more natural to me anyway. -- Alvaro Herrera http://www.CommandPrompt.com/ The PostgreSQL Company - Command Prompt, Inc.
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