Re: linking
От | Oliver Elphick |
---|---|
Тема | Re: linking |
Дата | |
Msg-id | 200103030221.f232LBG00549@linda.lfix.co.uk обсуждение исходный текст |
Ответ на | linking (si <s@remail.net>) |
Список | pgsql-novice |
si wrote: >Please can you help: >Insert into DEPARTMENT values ('Bedrock','Administration'); > >Insert into Employee values ('1','Slate','????'); > >How do I replace ???? to automatically get the DEPT_NO value? > >e.g. In theory I need to replace ???? with (select DEPT_NO from DEPARTMENT w >here location = 'Administration' and DESCRIPTION = 'Bedrock';) but I am >not sure how to do this all in 1 statement. > >The DEPT_NO is automatically created if no value is given, which is why I al >so need to create the DEPT relation automatically. In 7.1 you can simply do this: junk=# Insert into Employee values (1,'Slate', junk(# (select DEPT_NO from DEPARTMENT where DESCRIPTION = 'Administration' and location = 'Bedrock')); INSERT 2085500 1 junk=# select * from department; location | description | dept_no ----------+----------------+--------- Bedrock | Administration | 1 (1 row) junk=# select * from employee; empl_id | name_last | dept ---------+-----------+------ 1 | Slate | 1 (1 row) However, if you do this, you need a unique index on (location, description); at the moment you could have more than one dept_no for the same combination. -- Oliver Elphick Oliver.Elphick@lfix.co.uk Isle of Wight http://www.lfix.co.uk/oliver PGP: 1024R/32B8FAA1: 97 EA 1D 47 72 3F 28 47 6B 7E 39 CC 56 E4 C1 47 GPG: 1024D/3E1D0C1C: CA12 09E0 E8D5 8870 5839 932A 614D 4C34 3E1D 0C1C ======================================== "I will lift up mine eyes unto the hills, from whence cometh my help. My help cometh from the LORD, which made heaven and earth." Psalms 121:1,2
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