linking
От | si |
---|---|
Тема | linking |
Дата | |
Msg-id | 20010303005600.4EA0036F9@sitemail.everyone.net обсуждение исходный текст |
Ответы |
Re: linking
|
Список | pgsql-novice |
Please can you help: +--------------------------------------+ | DEPARTMENT | +----------+----------------+----------+ | LOCATION | DESCRIPTION | DEPT_NO | +----------+----------------+----------+ | Bedrock | Administration | 1 | | Bedrock | Quarry | 2 | | Redcliff | Stockpile | 3 | +----------+----------------+----------+ +-----------------------------+ | EMPLOYEE | +---------+------------+------+ | EMPL_ID | NAME_LAST | DEPT | +---------+------------+------+ | 1 | Slate | 1 | | 4 | Flintstone | 2 | | 5 | Rubble | 2 | | 7 | Rockhead | 3 | | 11 | Gravel | 1 | +---------+------------+------+ create sequence increment start 1 increment 1 maxvalue 2147483647 minvalue 1 cache 1; create table DEPARTMENT ( LOCATION varchar(30), DESCRIPTION varchar(30), DEPT_NO int unique not null default nextval('increment') primary key ); create table EMPLOYEE ( EMPL_ID int unique not null primary key, NAME_LAST varchar(20), DEPT int references DEPARTMENT (DEPT_NO) ); Insert into DEPARTMENT values ('Bedrock','Administration'); Insert into Employee values ('1','Slate','????'); How do I replace ???? to automatically get the DEPT_NO value? e.g. In theory I need to replace ???? with (select DEPT_NO from DEPARTMENT where location = 'Administration' and DESCRIPTION= 'Bedrock';) but I am not sure how to do this all in 1 statement. The DEPT_NO is automatically created if no value is given, which is why I also need to create the DEPT relation automatically. Thanks, Si _____________________________________________________________ Pick up your email anywhere in the world ---> http://www.remail.net
В списке pgsql-novice по дате отправления: