Обсуждение: SQL question, TOP 5 and all OTHERS

       count(DISTINCT inv_id) AS "# of Invoices"

FROM SpendTable

GROUP BY vendor_name

ORDER BY "# of Invoices" DESC LIMIT 5)
SELECT * FROM top5
UNION

SELECT 'all other' AS vendor_name,

       count(DISTINCT st.inv_id) AS "# of Invoices"

FROM SpendTable AS st

WHERE st.vendor_name NOT IN (SELECT vendor_name FROM top5)
ORDER BY "# of Invoices" DESC

Best regards,
--
Jean MAURICE
Grenoble - France - Europe
www.j-maurice.fr
www.atoutfox.org
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Hi,

 

I’m trying to get up-to-speed with PostgreSQL and have a dumb question. I have a basic query to pull the top 5 vendors that have sent me the most bills. I would like to lump all the other vendors into a row named “Other” and get a count of all those bills excluding the top 5. Below is the basic query.

 

SELECT vendor_name AS vendor_name,

       count(DISTINCT inv_id) AS "# of Invoices"

FROM SpendTable

GROUP BY vendor_name

ORDER BY "# of Invoices" DESC

LIMIT 5

 

Thanks,

Scott

-- 
J. MAURICE

Garanti sans virus. www.avg.com

On Mon, Jun 06, 2022 at 09:46:12PM +0200, Jean MAURICE wrote:
> Hi Scott,
> what about using a Common Table Expression and the clause WITH ?
> I am not at home now but you can write something like
> 
> WITH top5 AS (SELECT vendor_name AS vendor_name,
> 
> ?????? count(DISTINCT inv_id) AS "# of Invoices"
> 
> FROM SpendTable
> 
> GROUP BY vendor_name
> 
> ORDER BY "# of Invoices" DESC
> 
> LIMIT 5)
> SELECT * FROM top5
> UNION
> 
> SELECT 'all other' AS vendor_name,
> 
> ?????? count(DISTINCT st.inv_id) AS "# of Invoices"
> 
> FROM SpendTable AS st
> 
> WHERE st.vendor_name NOT IN (SELECT vendor_name FROM top5)
> 
> ORDER BY "# of Invoices" DESC

There might be a challenge with ties, especially if you don't order by the
vendor name since you could get different results even on the same data
set, depending on how the query plan goes. It depends on what the OP is
looking for, I guess.

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