Обсуждение: pgAdmin 4.20 and 4.21 cannot create foreign key

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pgAdmin 4.20 and 4.21 cannot create foreign key

От
Edson Richter
Дата:
Using PostgreSQL 9.6 on Linux Centos 7 x64 - yum standard installer.
pgAdmin 4.20 and 4.21 on Windows Server 2019 x64 - .exe standard installer.

I'm trying to create a foreign key using 4.20 and didn't wored: keep always asking to create a covering index.
Tryied in 4.20 and also in 4.21 with same results

Follow the screenshot of the error:


Вложения

Re: pgAdmin 4.20 and 4.21 cannot create foreign key

От
Khushboo Vashi
Дата:
Hi,


Thanks,
Khushboo

On Sun, May 3, 2020 at 12:20 AM Edson Richter <edsonrichter@hotmail.com> wrote:
Using PostgreSQL 9.6 on Linux Centos 7 x64 - yum standard installer.
pgAdmin 4.20 and 4.21 on Windows Server 2019 x64 - .exe standard installer.

I'm trying to create a foreign key using 4.20 and didn't wored: keep always asking to create a covering index.
Tryied in 4.20 and also in 4.21 with same results

Follow the screenshot of the error:


Вложения

Re: pgAdmin 4.20 and 4.21 cannot create foreign key

От
Akshay Joshi
Дата:
Hi Edson

I have tried on PostgreSQL 9.6 and 10, not able to reproduce the issue. Can you please provide the exact steps and the example table?

On Sun, May 3, 2020 at 12:20 AM Edson Richter <edsonrichter@hotmail.com> wrote:
Using PostgreSQL 9.6 on Linux Centos 7 x64 - yum standard installer.
pgAdmin 4.20 and 4.21 on Windows Server 2019 x64 - .exe standard installer.

I'm trying to create a foreign key using 4.20 and didn't wored: keep always asking to create a covering index.
Tryied in 4.20 and also in 4.21 with same results

Follow the screenshot of the error:




--
Thanks & Regards
Akshay Joshi
Sr. Software Architect
EnterpriseDB Software India Private Limited
Mobile: +91 976-788-8246
Вложения

Re: pgAdmin 4.20 and 4.21 cannot create foreign key

От
Doug Reed
Дата:
I've seen it as well.

On Mon, May 4, 2020 at 4:18 AM Akshay Joshi <akshay.joshi@enterprisedb.com> wrote:
Hi Edson

I have tried on PostgreSQL 9.6 and 10, not able to reproduce the issue. Can you please provide the exact steps and the example table?

On Sun, May 3, 2020 at 12:20 AM Edson Richter <edsonrichter@hotmail.com> wrote:
Using PostgreSQL 9.6 on Linux Centos 7 x64 - yum standard installer.
pgAdmin 4.20 and 4.21 on Windows Server 2019 x64 - .exe standard installer.

I'm trying to create a foreign key using 4.20 and didn't wored: keep always asking to create a covering index.
Tryied in 4.20 and also in 4.21 with same results

Follow the screenshot of the error:




--
Thanks & Regards
Akshay Joshi
Sr. Software Architect
EnterpriseDB Software India Private Limited
Mobile: +91 976-788-8246


--
Regards,

Doug
Вложения