Обсуждение: pg_fetch_array problem

Hi i am trying to build
previous and next links from a table selection, the code below stops working
at the line which says :

while ($dados = pg_fetch_array($limite)) {
    $nome = $dados["nome"];
    echo "Nome: $nome<br>";

the warning says:
Wrong parameter count for pg_fetch_array()

i get this code from a php mysql and try to adapt to my needs, is that any
parameter wrong? wich can be?


<?php

$conn = pg_connect("dbname=sondagem user=postgres");
?>
<?php
$busca = "SELECT nome AS data FROM aprovados ORDER BY nome ASC ";
?>
<?php
$total_reg = "10"; // número de registros por página
?>
<?php
if (!$pagina) {
    $pc = "1";
} else {
    $pc = $pagina;
}
?>
<?php
$inicio = $pc - 1;
$inicio = $inicio * $total_reg;
?>
<?php
$limite = pg_exec("$busca LIMIT $inicio,$total_reg");
$todos = pg_exec("$busca");

$tr = pg_numrows($todos); // verifica o número total de registros
$tp = $tr / $total_reg; // verifica o número total de páginas

// vamos criar a visualização
while ($dados = pg_fetch_array($limite)) {
    $nome = $dados["nome"];
    echo "Nome: $nome<br>";
}

// agora vamos criar os botões "Anterior e próximo"
$anterior = $pc -1;
$proximo = $pc +1;
if ($pc>1) {
    echo " <a href='?pagina=$anterior'><- Anterior</a> ";
}
echo "|";
if ($pc<$tp) {
    echo " <a href='?pagina=$proximo'>Próxima -></a>";
}
?>

________________________________________
A busca mais veloz e precisa da internet. Acesse agora: http://www.zoom.com.br.

hmm.. you could try..

for(var i=0; $dados = pg_fetch_array($limite, $i); i++) {
     $nome = $dados["nome"];
      echo "Name: $nome<BR>";
}

I believe your error is your not passing pg_fetch_array() the row you
wish to return.  It *may* or may not work that way.  But leaving it open
like that is sure to cause an error sooner or later.

Hope this helps
David

angelo.rigo@globo.com wrote:

>Hi i am trying to build
>previous and next links from a table selection, the code below stops working
>at the line which says :
>
>while ($dados = pg_fetch_array($limite)) {
>    $nome = $dados["nome"];
>    echo "Nome: $nome<br>";
>
>the warning says:
>Wrong parameter count for pg_fetch_array()
>
>i get this code from a php mysql and try to adapt to my needs, is that any
>parameter wrong? wich can be?
>
>
><?php
>
>$conn = pg_connect("dbname=sondagem user=postgres");
>?>
><?php
>$busca = "SELECT nome AS data FROM aprovados ORDER BY nome ASC ";
>?>
><?php
>$total_reg = "10"; // número de registros por página
>?>
><?php
>if (!$pagina) {
>    $pc = "1";
>} else {
>    $pc = $pagina;
>}
>?>
><?php
>$inicio = $pc - 1;
>$inicio = $inicio * $total_reg;
>?>
><?php
>$limite = pg_exec("$busca LIMIT $inicio,$total_reg");
>$todos = pg_exec("$busca");
>
>$tr = pg_numrows($todos); // verifica o número total de registros
>$tp = $tr / $total_reg; // verifica o número total de páginas
>
>// vamos criar a visualização
>while ($dados = pg_fetch_array($limite)) {
>    $nome = $dados["nome"];
>    echo "Nome: $nome<br>";
>}
>
>// agora vamos criar os botões "Anterior e próximo"
>$anterior = $pc -1;
>$proximo = $pc +1;
>if ($pc>1) {
>    echo " <a href='?pagina=$anterior'><- Anterior</a> ";
>}
>echo "|";
>if ($pc<$tp) {
>    echo " <a href='?pagina=$proximo'>Próxima -></a>";
>}
>?>
>
>________________________________________
>A busca mais veloz e precisa da internet. Acesse agora: http://www.zoom.com.br.
>
>
>
>---------------------------(end of broadcast)---------------------------
>TIP 4: Don't 'kill -9' the postmaster
>
>
>

What version of PHP are you running?  The autoincrementing nature of the
row value in pg_fetch_array wasn't included until PHP 4.1.0

On Thu, 8 Aug 2002 angelo.rigo@globo.com wrote:

> Hi i am trying to build
> previous and next links from a table selection, the code below stops working
> at the line which says :
>
> while ($dados = pg_fetch_array($limite)) {
>     $nome = $dados["nome"];
>     echo "Nome: $nome<br>";
>
> the warning says:
> Wrong parameter count for pg_fetch_array()
>
> i get this code from a php mysql and try to adapt to my needs, is that any
> parameter wrong? wich can be?
>
>
> <?php
>
> $conn = pg_connect("dbname=sondagem user=postgres");
> ?>
> <?php
> $busca = "SELECT nome AS data FROM aprovados ORDER BY nome ASC ";
> ?>
> <?php
> $total_reg = "10"; // número de registros por página
> ?>
> <?php
> if (!$pagina) {
>     $pc = "1";
> } else {
>     $pc = $pagina;
> }
> ?>
> <?php
> $inicio = $pc - 1;
> $inicio = $inicio * $total_reg;
> ?>
> <?php
> $limite = pg_exec("$busca LIMIT $inicio,$total_reg");
> $todos = pg_exec("$busca");
>
> $tr = pg_numrows($todos); // verifica o número total de registros
> $tp = $tr / $total_reg; // verifica o número total de páginas
>
> // vamos criar a visualização
> while ($dados = pg_fetch_array($limite)) {
>     $nome = $dados["nome"];
>     echo "Nome: $nome<br>";
> }
>
> // agora vamos criar os botões "Anterior e próximo"
> $anterior = $pc -1;
> $proximo = $pc +1;
> if ($pc>1) {
>     echo " <a href='?pagina=$anterior'><- Anterior</a> ";
> }
> echo "|";
> if ($pc<$tp) {
>     echo " <a href='?pagina=$proximo'>Próxima -></a>";
> }
> ?>
>
> ________________________________________
> A busca mais veloz e precisa da internet. Acesse agora: http://www.zoom.com.br.
>
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 4: Don't 'kill -9' the postmaster
>

On Thu, 8 Aug 2002, David C. Brown wrote:

> hmm.. you could try..
>
> for(var i=0; $dados = pg_fetch_array($limite, $i); i++) {
>      $nome = $dados["nome"];
>       echo "Name: $nome<BR>";
> }
>
> I believe your error is your not passing pg_fetch_array() the row you
> wish to return.  It *may* or may not work that way.  But leaving it open
> like that is sure to cause an error sooner or later.

Actually, no.  In the latest and greatest version of PHP, pg_fetch_array
returns false when it runs out of rows, so you can just use:

while ($row = pg_fetch_array){
    dosomething here...
}