Re: How to use an alias name in the current select
От | Dimitri Fontaine |
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Тема | Re: How to use an alias name in the current select |
Дата | |
Msg-id | m2d3ytwn8h.fsf@hi-media.com обсуждение исходный текст |
Ответ на | How to use an alias name in the current select (Guy Deleeuw <G.De_Leeuw@eurofer.be>) |
Ответы |
Re: How to use an alias name in the current select
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Список | pgsql-admin |
Hi, Guy Deleeuw <G.De_Leeuw@eurofer.be> writes: > SELECT > t_orders_articles.k_id AS k_id > ,t_orders_articles.quantity AS order_qty > ,(SELECT sum(quantity) FROM t_deliveries_articles WHERE article_id = > t_orders_articles.k_id) AS delivery_qty > , (t_orders_articles.quantity - delivery_qty) AS qty > FROM t_orders_articles > ......; > > How can I make that without having 2 select call ? Put it as a relation in a subquery, or use WITH if using 8.4. SELECT k_id, order_qty, quantity, delivery_qty, quantity - delivery_qty as qty FROM ( SELECT t_orders_articles.k_id AS k_id ,t_orders_articles.quantity AS order_qty ,(SELECT sum(quantity) FROM t_deliveries_articles WHERE article_id = t_orders_articles.k_id) AS delivery_qty , t_orders_articles.quantity FROM t_orders_articles ) as t; Or WITH t AS ( SELECT t_orders_articles.k_id AS k_id ,t_orders_articles.quantity AS order_qty ,(SELECT sum(quantity) FROM t_deliveries_articles WHERE article_id = t_orders_articles.k_id) AS delivery_qty , t_orders_articles.quantity FROM t_orders_articles ) SELECT k_id, order_qty, quantity, delivery_qty, quantity - delivery_qty as qty FROM t; Regards, -- dim
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