Re: Need some help with a query (uniq -c)
От | Scott Marlowe |
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Тема | Re: Need some help with a query (uniq -c) |
Дата | |
Msg-id | g2gdcc563d11004121131l59038899pf64e31ed0e9d548f@mail.gmail.com обсуждение исходный текст |
Ответ на | Need some help with a query (uniq -c) (A B <gentosaker@gmail.com>) |
Ответы |
Re: Need some help with a query (uniq -c)
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Список | pgsql-general |
On Mon, Apr 12, 2010 at 12:22 PM, A B <gentosaker@gmail.com> wrote: > Hello! > > I have a table (think of it as a table of log messages) > > time | message > ----------------------- > 1 | a > 2 | b > 3 | b > 4 | b > 5 | a > > the three 'b' are the same message, so I would like to write a query > that would give me a result that is similar to what the unix command > "uniq -c" would give: > > first | message | last | count > -------------------------------------- > 1 | a | 1 | 1 > 2 | b | 4 | 3 <--- here it squeezes > similar consecutive messages into a single row > 5 | a | 5 | 1 > > How do I write such a command? Pretty straight ahead: select min(t), message, max(t), count(*) from table group by message.
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