Re: Where clause
От | news.gmane.org |
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Тема | Re: Where clause |
Дата | |
Msg-id | f5ravm$37c$1@sea.gmane.org обсуждение исходный текст |
Ответ на | Where clause (Michael Landin Hostbaek <mich@the-lab.org>) |
Ответы |
Re: Where clause
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Список | pgsql-sql |
Michael Landin Hostbaek skrev: > Hello, > > I have a table called tracking, with a contactid varchar, click bool, > view bool and cid varchar. > > I would like to put the following into one single query if possible: > > // Number of clicks > select cid,count(distinct contactid) from tracking where click = > true group by cid; > > // Number of views > select cid,count(distinct contactid) from tracking where view = > true group by cid; Untested, not the cleverest formulation, but something like this should work: SELECT * FROM ( select cid,count(distinct contactid) from tracking where click = true group by cid ) c1 FULL OUTER JOIN ( select cid,count(distinct contactid) from tracking where view = true group by cid ) c2 USING (cid);
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