Re: Transaction progress
От | Manfred Koizar |
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Тема | Re: Transaction progress |
Дата | |
Msg-id | e3hn2v05vp7tpg3t7mk7vlg38dgu9oaksb@4ax.com обсуждение исходный текст |
Ответ на | Re: Transaction progress (Pablo Yaggi <pyaggi@aulamagna.com.ar>) |
Ответы |
Re: Transaction progress
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Список | pgsql-general |
On Sun, 19 Jan 2003 22:23:49 -0300, Pablo Yaggi <pyaggi@aulamagna.com.ar> wrote: >I had also created and index inars_nocontrib_perm1_inx this way: > >create index inars_nocontrib_perm1_inx on inars_nocontrib_perm1 (ano,mes,cuil,cuit) How long did this take? Knowing this can help estimating sort cost. As I told you I have no gut feeling for large sorts; simply not enough experience ... Does this index still exist? >but the planner didn't use it, as you can see. That's the way I broke the config file >before (enable_seqscan=false). If your tuples are physically ordered by ano, mes, cuil, cuit, then an index scan is almost as fast as a seq scan and there is no need for a separate sort step. Unfortunately the planner has its problems with multi column indices. So if *you* know that tuples are stored in index order in both relations, this might indeed be a good case for setting enable_seqscan=off. >based on your experience/calculation, could you give some advice, do I have to increase sort memory ? Definitely! I just don't know how much :-( A shoot into the dark: 60000 or even 120000, but don't leave it that high when you go multiuser. >do I have to change the query ? If the sort turns out to be the problem and it is unavoidable, I'd do several smaller updates: UPDATE ... WHERE ano=2000::int2 AND mes=1::int2; UPDATE ... WHERE ano=2000::int2 AND mes=2::int2; ... UPDATE ... WHERE ano=2003::int2 AND mes=1::int2; >... well something, the query is running from about 28 hours, do I stop it >and try something else ? is there anyway to check how long, even estimated, it will take to finish ? Not that I know of, except watching your disk files grow and trying to estimate how many tuples have already been updated ... Servus Manfred
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