Re: iterating over DictRow

On 9/25/20 3:25 PM, Karsten Hilbert wrote:
> On Fri, Sep 25, 2020 at 03:19:12PM -0700, Adrian Klaver wrote:
> 
>>> Sure, there's a number of solutions to my immediate problem,
>>> the fitting of which is
>>>
>>>     for key in dict(DictRow):
>>>
>>> That's the best fit because my
>>>
>>>     def _escape_dict(the_dict, ...):
>>>
>>> was inaptly named. It should have been (and now is)
>>>
>>>     def _escape_dict_like(dict_like, ...):
>>>
>>> within which
>>>
>>>     dict(dict_like)
>>>
>>> is quite the thing to do despite having to make something a
>>> duck which already nearly quacks like one is somehwat
>>> unfortunate.
>>
>> I'm pretty sure DictRow has had the same behavior for some time so:
>>
>> Are you migrating from Python 2?
> 
> I did not too long ago.

So that explains the error that popped up.

> 
>> Or what changed that made this show up?
> 
> At the very core ?  My grandpa was admitted to a hospital :-)

Sorry to hear that, it's a trial.

> 
> Karsten
> --
> GPG  40BE 5B0E C98E 1713 AFA6  5BC0 3BEA AC80 7D4F C89B
> 
> 


-- 
Adrian Klaver
adrian.klaver@aklaver.com