Re: sorting by day of the week

Nevermind, I figured out that I just needed to do it like this:

SELECT to_char( logtime, 'Dy'),count(*),to_char( logtime, 'D') FROM 
sclog WHERE date_trunc('day', logtime) > current_date + '7 day 
ago'::interval group by to_char( logtime, 'Dy'),to_char( logtime, 'D') 
ORDER BY to_char( logtime, 'D') DESC;

It is interesting that I can't put to_char( logtime, 'D') in the the 
group by without putting it in the select.


Joseph Shraibman wrote:
> p8:owl=>SELECT to_char( logtime, 'Dy'),count(*) FROM logtab WHERE 
> date_trunc('day', logtime) > current_date + '7 day ago'::interval group 
> by to_char( logtime, 'Dy') ORDER BY to_char( logtime, 'Dy') DESC;
>  to_char | count
> ---------+-------
>  Wed     |  1447
>  Tue     |   618
>  Thu     |  1161
>  Sun     |   230
>  Sat     |   362
>  Mon     |   760
>  Fri     |  1281
> (7 rows)
> 
> The problem is that I want those results sorted in day of week order, 
> not text order of the day name, so I tried this:
> 
> p8:owl=>SELECT to_char( logtime, 'Dy'),count(*) FROM sclog WHERE 
> date_trunc('day', logtime) > current_date + '7 day ago'::interval group 
> by to_char( logtime, 'Dy') ORDER BY to_char( logtime, 'D') DESC;
> ERROR:  column "sclog.logtime" must appear in the GROUP BY clause or be 
> used in an aggregate function
> 
> Now obviously I don't want to group by logtime (a timestamp) so how do I 
> work around this?  What I really need is a function that converts from 
> the char representation to a day of week number or vice versa.  I also 
> have the same problem with month names.