Re: DRAFT 9.6 release
| От | Josh Berkus |
|---|---|
| Тема | Re: DRAFT 9.6 release |
| Дата | |
| Msg-id | dee02090-abc8-4b83-c90a-40a44ce3e470@agliodbs.com обсуждение исходный текст |
| Ответ на | DRAFT 9.6 release (Josh Berkus <josh@agliodbs.com>) |
| Ответы |
Re: DRAFT 9.6 release
|
| Список | pgsql-advocacy |
On 08/30/2016 06:20 PM, Josh Berkus wrote: > On 08/30/2016 06:12 PM, Michael Paquier wrote: > >> Really? Here are the doc quotes that I guess matter, and I read that >> differently than you do: >> If any of the current synchronous standbys disconnects for whatever >> reason, it will be replaced immediately with the next-highest-priority >> standby. >> [...] >> For example, a setting of 3 (s1, s2, s3, s4) makes transaction commits >> wait until their WAL records are received by *three higher-priority >> standbys* chosen from standby servers s1, s2, s3 and s4. >> >> This clearly says that we wait for the servers that have a higher >> priority, meaning that we do *not* wait for any k elements in a set of >> n listed, but suggest that the order of the element matters. > > Yeah, the problem is that "higher priority" isn't defined, and could > mean a lot of things. It *is* defined in the actual section on > synchronous standby, though (25.2.8.2.); maybe what we need is less docs > under the GUC and more references to that? > > Otherwise, you're going to have lots of people confused that it's > actually quorum commit, as witnessed by the current discussion. Right > now what's in the GUC doc page appears to be complete but isn't. Also, if I do this: 2 ( g1, g2, g3 ) ... and g1, g2 and g3 are *groups* of three standbys each, what happens? Does it wait for one or more responses from g1 and from g2, or does getting two responses from g1 trigger a commit? -- -- Josh Berkus Red Hat OSAS (any opinions are my own)
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