Re: SELECT DISTINCT ON and ORDER BY
От | josep porres |
---|---|
Тема | Re: SELECT DISTINCT ON and ORDER BY |
Дата | |
Msg-id | d2d532610803280615k45ca35f2m2b96184ade806780@mail.gmail.com обсуждение исходный текст |
Ответ на | SELECT DISTINCT ON and ORDER BY ("Stanislav Raskin" <sr@brainswell.de>) |
Ответы |
Re: SELECT DISTINCT ON and ORDER BY
Re: SELECT DISTINCT ON and ORDER BY |
Список | pgsql-general |
select value, max(id) as id, max(order_field) as order_field
from mytable
group by value
order by 3
Hello everybody,
I have a table like this one:
id value order_field
1 10 3
2 12 4
3 10 1
4 5 8
5 12 2
What I want to do, is to do something like
SLECT DISTINCT ON (my_table.value)
my_table.id, my_table.value, my_table.order_field
FROM my_table
ORDER BY order_field
Hence selecting rows with distinct values, but primarily ordered by order_field, instead of value, which is requires by DISTINCT ON.
The result in this case should be:
id value order_field
3 10 1
5 12 2
4 5 8
How do I do this? I do need order_field in the select list to use it in the ORDER statement, which is why – as far as I can see – GROUP BY and SELECT DISTINCT are useless. Did I miss out on something?
Thank you in advance
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