Sorted group by

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От Matthew Wakeling
Тема Sorted group by
Дата
Msg-id alpine.DEB.2.00.1008101627440.2654@aragorn.flymine.org
обсуждение исходный текст
Ответы Re: Sorted group by  (Thomas Kellerer <spam_eater@gmx.net>)
Re: Sorted group by  (hubert depesz lubaczewski <depesz@depesz.com>)
Re: Sorted group by  ("Kevin Grittner" <Kevin.Grittner@wicourts.gov>)
Re: Sorted group by  (Alvaro Herrera <alvherre@commandprompt.com>)
Список pgsql-performance
I'm trying to eke a little bit more performance out of an application, and
I was wondering if there was a better way to do the following:

I am trying to retrieve, for many sets of rows grouped on a couple of
fields, the value of an ungrouped field where the row has the highest
value in another ungrouped field. For instance, I have the following table
setup:

group  | whatever type
value  | whatever type
number | int
Index: group

I then have rows like this:

group     | value         | number
-------------------------------------
Foo       | foo           | 1
Foo       | turnips       | 2
Bar       | albatross     | 3
Bar       | monkey        | 4

I want to receive results like this:

group     | value
-----------------------
Foo       | turnips
Bar       | monkey

Currently, I do this in my application by ordering by the number and only
using the last value. I imagine that this is something that can be done in
the new Postgres 9, with a sorted group by - something like this:

SELECT group, LAST(value, ORDER BY number) FROM table GROUP BY group

Is this something that is already built in, or would I have to write my
own LAST aggregate function?

Matthew

--
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 things like "ha-ha-ha", but in a sympathetic tone of voice
                                        -- Computer Science Lecturer

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