Struggling with c functions
От | Olivier PRENANT |
---|---|
Тема | Struggling with c functions |
Дата | |
Msg-id | Pine.UW2.4.21.0104282344360.12890-100000@server.pyrenet.fr обсуждение исходный текст |
Список | pgsql-hackers |
Hi all, I'm rewriting my OLD crypt (Thanks to Henrique) C_fonction to version 0 forms : I have this C file compiled OK to a shared library: /* * * Henrique Pantarotto (scanner@cepa.com.br) * Funcao para encriptar senhas (Function to encrypt passwords) * September 1999 * * PS: Note that all crypted passwords are created with salt "HP" (my name * initials..) You can change that, or if you know C, you can do in a way * that it will pick two random characters (the way it should really be). * */ #include <strings.h> #include <unistd.h> #include <postgres.h> text *post_crypt(text *user) {text *password;char * crypt();long now=time((long *) 0);int len;char salt[7]="PY", *crypted;/*strcpy(salt,l64a(now)); salt[3]='\0';*/crypted=crypt(VARDATA(user),salt);len=strlen(crypted);password= palloc((int32) 13 + VARHDRSZ);VARATT_SIZEP(password)=(int32) VARHDRSZ + 13;memcpy(VARDATA(password),crypted,len);return password; } text *sql_crypt(text *user,text *salt) { text *password; char * crypt(), *crypted; int len; char s[3]; strncpy(s,VARDATA(salt),2); s[2]='\0'; crypted=crypt(VARDATA(user),s);len=strlen(crypted); password=palloc((int32) 13 + VARHDRSZ); VARATT_SIZEP(password)=(int32)13 + VARHDRSZ; memcpy(VARDATA(password),crypted,len); return password; } /* Compile using something like this: gcc -I/home/postgres/postgresql-6.5.1/src/include -I/home/postgres/postgresql-6.5.1/src/backend -O2 -Wall -Wmissing-prototypes-fpic -I/home/postgres/postgresql-6.5.1/src/include -c -o encrypt.o encrypt.c gcc -shared -o encrypt.so encrypt.o And last, you create the trigger in PostgreSQL using this: create function encrypt(text) returns text as '/usr/local/pgsql/lib/encrypt.so' language 'c'; If everything is okay, you'll probably have: select encrypt('secret') working and showing: encrypt ------------ HPK1Jt2NX21G. (1 row) */ I have defined to SQL function: CREATE FUNCTION post_crypt(text) RETURNS text AS 'xxxx/encrypt.so' CREATE FUNCTION sql_cypt(text,text) RETURNS text AS 'xxxx/encrypt.so'; WHY on earth does SELECT post_crypt('test'),sql_crypt('test','PY') NOT GIVE the same result??? Please help, This is most urgent (My customer can't use this function anymore); it worked OK with 7.0.3!! Regards, -- Olivier PRENANT Tel: +33-5-61-50-97-00 (Work) Quartier d'Harraud Turrou +33-5-61-50-97-01 (Fax) 31190 AUTERIVE +33-6-07-63-80-64 (GSM) FRANCE Email: ohp@pyrenet.fr ------------------------------------------------------------------------------ Make your life a dream, make your dream a reality. (St Exupery)
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