query help request [2x]
От | Andrei Ivanov |
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Тема | query help request [2x] |
Дата | |
Msg-id | Pine.LNX.4.50L0.0304012208110.2309-100000@webdev.ines.ro обсуждение исходный текст |
Ответы |
Re: query help request [2x]
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Список | pgsql-novice |
Hello, I have 3 tables: users: id serial primary key, nick varchar and other stuff profiles: user_id which is a foreign key pointing to users(id), other things about the user (a user doesn't have to own a profile, but in this listing I want only users with a profile) pictures: id serial pk, user_id foreign key, picture varchar (a user doesn't have to own a picture or more) What I want to do is to list all the users, something like this: id, nick, stuff from profile, has_picture has_picture is a flag which indicates if the user has a picture or not. First time I did something like this: SELECT u.id, u.nick, pr.keywords, COALESCE(p.id, 0) AS has_picture FROM users u JOIN profiles pr ON u.id = pr.user_id LEFT JOIN pictures p ON u.user_id = p.user_id; but if a user has more than 1 picture, it is listed more then once. Then I came up with this: SELECT u.id, u.nick, pr.keywords, COALESCE((SELECT id FROM pictures WHERE user_id = u.id), 0) AS has_picture FROM users u JOIN profiles pr ON u.id = pr.user_id; but, if I understand it correctly, for each user, it will issue a query on the pictures table to find a picture for that user, which I think it's an overkill. How can I do this right ? (I hope I didn't embarrassed myself by overlooking an obvious answer.) Thanks
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