Re: novice question about NOTICE:...
От | Doug Silver |
---|---|
Тема | Re: novice question about NOTICE:... |
Дата | |
Msg-id | Pine.LNX.4.21.0204031251110.22347-100000@danzig.sd.quantified.net обсуждение исходный текст |
Ответ на | novice question about NOTICE:... (Lloyd Vancil <lev@apple.com>) |
Список | pgsql-novice |
On Wed, 3 Apr 2002, Lloyd Vancil wrote: > Tried to search the novice archives and the engine just never > returns an answer. This is probably a pretty common question so I > hope I'll get a quick answer. > > > I have two tables cgidat and tierdat. > I want to select all occurrences of data in cgidat where > cgidat.state = testing and cgidat.lang = tierdat.lang and > tierdat.tier = 0 > > so I did > > > select oid, lang from cgidat where cgidat.state = 'testing' and > cgidat.lang = tiredat.lang and tierdat.tier = '0' order by lang; > > I get the expected results but I also get > Adding missing FROM-clause entry for table "tierdat" > > > Huh? > > Thanks > Lloyd > > That was mighty nice of Postgres to fix your query -- I didn't know it would do that. You're doing a join from two tables, cgidat and tierdat, so you must include them in your FROM clause: select oid, lang from cgidat, tierdat where cgidat.state = 'testing' and cgidat.lang = tiredat.lang and tierdat.tier = '0' order by lang; or using aliases (a must when you start joining several tables): select c.oid,c.lang from cgidat c, tierdat t where c.state='testing' and c.lang = t.lang and t.tier ='0' order by c.lang -- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Doug Silver Network Manager Quantified Systems, Inc ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
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