Re: [SQL] select with group by problem
От | neko@kredit.sth.szif.hu |
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Тема | Re: [SQL] select with group by problem |
Дата | |
Msg-id | Pine.LNX.4.10.9912171650470.23844-100000@kredit.sth.szif.hu обсуждение исходный текст |
Ответ на | Re: [SQL] select with group by problem (<kaiq@realtyideas.com>) |
Список | pgsql-sql |
> > xtra=> select * from warenkorb; > > cookie|datum|artnr|artnr1|artnr2|artikelname|farbe|groesse|menge|preis > > ------+-----+-----+------+------+-----------+-----+-------+-----+----- > > (0 rows) > > > > xtra=> SELECT artnr, artnr1, artnr2, artikelname, farbe, groesse, SUM( > > menge ), > > preis FROM warenkorb WHERE cookie = 'asdfasdf' GROUP BY artnr, artnr1, > > artnr2, > > artikelname, farbe, groesse, preis; > > artnr|artnr1|artnr2|artikelname|farbe|groesse|sum|preis > > -----+------+------+-----------+-----+-------+---+----- > > | | | | | | | > > (1 row) try this: xtra=> SELECT artnr, artnr1, artnr2, artikelname, farbe, groesse, SUM(menge), xtra-> preis FROM warenkorb WHERE cookie = 'asdfasdf' GROUP BY artnr, artnr1, xtra-> artnr2, artikelname, farbe, groesse, preis HAVING count(*)>0;
В списке pgsql-sql по дате отправления: