Re: [SQL] select a part of a name
От | |
---|---|
Тема | Re: [SQL] select a part of a name |
Дата | |
Msg-id | Pine.LNX.4.10.9912080946250.2267-100000@picasso.realtyideas.com обсуждение исходный текст |
Ответ на | Re: [SQL] select a part of a name (Vladimir Terziev <vlady@school.digsys.bg>) |
Список | pgsql-sql |
use: where name like '%names%' On Wed, 8 Dec 1999, Vladimir Terziev wrote: > > > You must write: > > select * from TEST where name ~ '&name'; > > This will match all names containing &name > > > Vladimir > > > > On Wed, 8 Dec 1999, Fred Schoonewille wrote: > > > Hi, > > > > I am trying to select a part of a name from the columm NAME, > > > > e.g. sql asks the user for input like: jone > > > > sql should give all names which begin with or containing 'jone' > > > > -jones > > -Tom-Jones > > > > Working with: > > > > select * from TEST > > where NAME= '&name' > > > > finds only exact matches > > > > Can I use e.g. % ? > > -- > > > > ----------------------------------- > > Fred Schoonewille > > > > Applicatiebeheer > > Computer Ondersteuning Hoboken > > ----------------------------------- > > http://www.eur.nl/fgg/coh > > ------------------------------------------------------- > > > > > > > > > > > > ************ > > > > > > > ************ >
В списке pgsql-sql по дате отправления: