question 2
От | ZioBudda |
---|---|
Тема | question 2 |
Дата | |
Msg-id | Pine.LNX.4.03.9812041905200.456-100000@michel.enter.it обсуждение исходный текст |
Список | pgsql-general |
Hi again, I have this query : select prestito.*, libro.tipo,libro.id_libro from prestito,libro where prestito.id_libro = libro.id_libro_key that return me (correct!): id_libro|id_utente|data_prestito|visto|notifica1|notifica2|notifica3|tipo|id_libro --------+---------+-------------+-----+---------+---------+---------+----+-------- 12| 37| 12-04-1998|f | | | | 1|s1 13| 37| 12-04-1998|f | | | | 2|k1 (2 rows) but if you see the item libro.id_libro is id_libro (s1,k1) and in the prestito.* there is another id_libro (11,12). Now I want to know how can I select the second "id_lib ro". "Il divertimento e' giusto se la scimmia ci prende gusto" -- Italian Linux Press: http://ziobudda.enter.it/ILP/ -- Morelli 'ZioBudda' Davide Michel - Member of Pluto Linux User Group michel@michel.enter.it - http://ziobudda.enter.it/ Linux Problem? Ask to linux@media.dsi.unimi.it "/dev/ziobudda: access to /var/tmp/beer denied, use /var/adm/pineapple"
В списке pgsql-general по дате отправления: