psql and shell scripts
От | Michael Fork |
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Тема | psql and shell scripts |
Дата | |
Msg-id | Pine.BSI.4.21.0103252342290.6476-100000@glass.toledolink.com обсуждение исходный текст |
Ответы |
Re: psql and shell scripts
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Список | pgsql-general |
I am running the following command from a bash script: /usr/local/pgsql/bin/psql -c "BEGIN; CREATE TEMP TABLE radacct_archive_temp AS SELECT * FROM radacct_archive WHERE date_part('month', tstamp) = ${RADACCT_MONTH} AND date_part('year', tstamp) = ${RADACCT_YEAR}; UPDATE radacct_archive_te mp SET framedipaddress = NULL WHERE framedipaddress = ''; COPY radacct_archive_t emp TO '$COPY_RADACCT'; COMMIT;" $MAIN_DB which produces this entry in the log file: query: BEGIN; CREATE TEMP TABLE radacct_archive_temp AS SELECT * FROM radacct_archive WHERE date_part('month', tstamp) = 06 AND date_part('year', tstamp) = 2000; UPDATE radacct_archive_temp SET framedipaddress = NULL WHERE framedipaddress = ''; COPY radacct_archive_temp TO '/usr/local/pgsql/radius.R73573'; COMMIT; which shows all of the variables have been properly substituted, leaving (what appears to me) valid SQL. However, the script produces the error: ERROR: Relation 'radacct_archive_temp' does not exist which doesn't make sense to me, as it is clearly created first, and inside of a transaction. If I paste exactly what is in the log into a psql window, it works as expected. What am I missing (it has to be simple...) Thanks! Michael Fork - CCNA - MCP - A+ Network Support - Toledo Internet Access - Toledo Ohio
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