RE: [HACKERS] Should the following work...?
От | The Hermit Hacker |
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Тема | RE: [HACKERS] Should the following work...? |
Дата | |
Msg-id | Pine.BSF.4.05.9903301442590.55565-100000@thelab.hub.org обсуждение исходный текст |
Ответ на | RE: [HACKERS] Should the following work...? (The Hermit Hacker <scrappy@hub.org>) |
Список | pgsql-hackers |
Just talked to one of our Oracle guru's here at hte office, and he had to shake his head a bit :) To find duplicate records, or, at least, data in a particular field, he suggests just doing: SELECT id,count(1) FROM clientsGROUP BY id HAVING count(1) > 1; A nice, clean, simple solution :) On Tue, 30 Mar 1999, The Hermit Hacker wrote: > > Using: > > select id > from clients > where id = ( select id > from clients > group by id > having count(id) = 1 ) ; > > > I get: > > ERROR: rewrite: aggregate column of view must be at rigth side in qual > > > > On Tue, 30 Mar 1999, Jackson, DeJuan wrote: > > > > select id > > > from clients > > > where id = ( select id > > > from clients > > > where count(id) = 1 ) ; > > > The error I get is that you can't do the AGGREGATE int he > > > WHERE clause, > > > but this is with a pre-v6.5 server too...technically, should > > > the above be > > > possible? > > I believe instead of WHERE that should be a HAVING clause. > > But I'm not sure PostgreSQL can handle a HAVING in a sub-select. > > > > -DEJ > > > > Marc G. Fournier ICQ#7615664 IRC Nick: Scrappy > Systems Administrator @ hub.org > primary: scrappy@hub.org secondary: scrappy@{freebsd|postgresql}.org > > Marc G. Fournier ICQ#7615664 IRC Nick: Scrappy Systems Administrator @ hub.org primary: scrappy@hub.org secondary: scrappy@{freebsd|postgresql}.org
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