Re: Data partitioning
От | Nick Fankhauser |
---|---|
Тема | Re: Data partitioning |
Дата | |
Msg-id | NEBBLAAHGLEEPCGOBHDGEEJIEBAA.nickf@ontko.com обсуждение исходный текст |
Ответ на | Data partitioning (Ravindra Wankar <rwankar@iname.com>) |
Список | pgsql-admin |
I don't know what your application looks like, but we're handling a similar situation by using several databases in a single cluster. In our case, the apps are JDBC-based, so it is possible to open a connection pool to each database & easily point the same application code at different sources. This does *not* allow queries across the databases, but *does* allow us to use a single instance of the application to serve up data from different databases depending on who is asking for it. Would this address your needs? -Nick -------------------------------------------------------------------------- Nick Fankhauser nickf@ontko.com Phone 1.765.935.4283 Fax 1.765.962.9788 Ray Ontko & Co. Software Consulting Services http://www.ontko.com/ > -----Original Message----- > From: pgsql-admin-owner@postgresql.org > [mailto:pgsql-admin-owner@postgresql.org]On Behalf Of Ravindra Wankar > Sent: Thursday, December 20, 2001 2:02 AM > To: pgsql-admin@postgresql.org > Subject: [ADMIN] Data partitioning > > > > We offer a web based application to companies. By keeping a company_id > in the schema we differentiate the data amongst companies. e.g the user > table has a company_id field to distinguish users between companies. > > However, most companies are feeling "insecure" about their data not > being stored separately from others. Also from a maintenance perspective > it seems it might be better. e.g restoring the data of an individual > company will be impossible. > > Is there a way to handle this? Preferably using a single database? > > Thanks, > -- Ravi. > > > ---------------------------(end of broadcast)--------------------------- > TIP 2: you can get off all lists at once with the unregister command > (send "unregister YourEmailAddressHere" to majordomo@postgresql.org) >
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