Re: DISTINCT *and* ORDER BY in aggregate functions on expressions(!)y
От | Alban Hertroys |
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Тема | Re: DISTINCT *and* ORDER BY in aggregate functions on expressions(!)y |
Дата | |
Msg-id | D9BE942C-58B4-48D0-9DA1-2B7514BA4881@gmail.com обсуждение исходный текст |
Ответ на | Re: DISTINCT *and* ORDER BY in aggregate functions on expressions(!)y (Thorsten Glaser <tg@evolvis.org>) |
Ответы |
Re: DISTINCT *and* ORDER BY in aggregate functions on expressions(!)y
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Список | pgsql-general |
> On 28 Feb 2023, at 3:54, Thorsten Glaser <tg@evolvis.org> wrote: (…) >> Well, that may be what you want, but it's not what you wrote in >> the query. Follow David's advice and do > […] >> I'm pretty sure that this will only incur one evaluation of the >> common subexpression, so even though it's tedious to type it's not >> inefficient. > > Thanks. But I fear it’s not as simple as you wrote. More like: > > jsonb_build_object('opening_times', > jsonb_agg(DISTINCT jsonb_build_object( > 'weekday', cot.weekday, > 'from_hour', cot.from_hour, > 'to_hour', cot.to_hour) > ORDER BY > jsonb_build_object( > 'weekday', cot.weekday, > 'from_hour', cot.from_hour, > 'to_hour', cot.to_hour)->>'weekday', > jsonb_build_object( > 'weekday', cot.weekday, > 'from_hour', cot.from_hour, > 'to_hour', cot.to_hour)->>'from_hour', > jsonb_build_object( > 'weekday', cot.weekday, > 'from_hour', cot.from_hour, > 'to_hour', cot.to_hour)->>'to_hour') > ) > > Isn’t that more like it? Perhaps you can use a lateral cross join to get the result of jsonb_build_object as a jsonb value to pass around? Alban Hertroys -- If you can't see the forest for the trees, cut the trees and you'll find there is no forest.
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