Re: Issue with listing same tablenames from different schemas in the search_path
От | Nikhil Sontakke |
---|---|
Тема | Re: Issue with listing same tablenames from different schemas in the search_path |
Дата | |
Msg-id | CANgU5ZemraTtyj7T-TqKgnRpdehi90z7A2MDku2EOZbAQFkG5g@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Issue with listing same tablenames from different schemas in the search_path (Heikki Linnakangas <heikki.linnakangas@enterprisedb.com>) |
Список | pgsql-hackers |
postgres=#create table public.sample(x int);
Hmmm, ok. Makes sense after reading the documentation, but seems a bit surprising/confusing at first glance. Never mind.
Regards,
Nikhils
No, that's the way it's designed to work. It shows the objects that are visible to you, without schema-qualifying them. See http://www.postgresql.org/docs/9.0/interactive/app-psql.html#APP-PSQL-PATTERNS :postgres=#create schema new;
postgres=#create table new.sample(x int);
postgres=#set search_path=public,new;
postgres=#\dt
Schema | Name | Type | Owner
-------------------------------------------
public | sample | table | postgres
(1 row)
We should have seen two entries in the above listing. So looks like a bug to
me.
Hmmm, ok. Makes sense after reading the documentation, but seems a bit surprising/confusing at first glance. Never mind.
Regards,
Nikhils
Whenever the pattern parameter is omitted completely, the \d commands display all objects that are visible in the current schema search path — this is equivalent to using * as the pattern. (An object is said to be visible if its containing schema is in the search path and no object of the same kind and name appears earlier in the search path. This is equivalent to the statement that the object can be referenced by name without explicit schema qualification.) To see all objects in the database regardless of visibility, use *.* as the pattern.
--
Heikki Linnakangas
EnterpriseDB http://www.enterprisedb.com
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