Re: Add proper planner support for ORDER BY / DISTINCT aggregates
От | Richard Guo |
---|---|
Тема | Re: Add proper planner support for ORDER BY / DISTINCT aggregates |
Дата | |
Msg-id | CAMbWs4_hAK6+0Gk=vZX+ikSFBx=6981iFLGkgLObDkvvGpjogg@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Add proper planner support for ORDER BY / DISTINCT aggregates (David Rowley <dgrowleyml@gmail.com>) |
Ответы |
Re: Add proper planner support for ORDER BY / DISTINCT aggregates
|
Список | pgsql-hackers |
On Tue, Jul 26, 2022 at 7:38 AM David Rowley <dgrowleyml@gmail.com> wrote:
On Fri, 22 Jul 2022 at 21:33, Richard Guo <guofenglinux@gmail.com> wrote:
> I can see this problem with
> the query below:
>
> select max(b order by b), max(a order by a) from t group by a;
>
> When processing the first aggregate, we compose the 'currpathkeys' as
> {a, b} and mark this aggregate in 'aggindexes'. When it comes to the
> second aggregate, we compose its pathkeys as {a} and decide that it is
> not stronger than 'currpathkeys'. So the second aggregate is not
> recorded in 'aggindexes'. As a result, we fail to mark aggpresorted for
> the second aggregate.
Yeah, you're right. I have a missing check to see if currpathkeys are
better than the pathkeys for the current aggregate. In your example
case we'd have still processed the 2nd aggregate the old way instead
of realising we could take the new pre-sorted path for faster
processing.
I've adjusted that in the attached to make it properly include the
case where currpathkeys are better.
Also I'm wondering if it's possible to take into consideration the
ordering indicated by existing indexes when determining the pathkeys. So
that for the query below we can avoid the Incremental Sort node if we
consider that there is an index on t(a, c):
# explain (costs off) select max(b order by b), max(c order by c) from t group by a;
QUERY PLAN
---------------------------------------------
GroupAggregate
Group Key: a
-> Incremental Sort
Sort Key: a, b
Presorted Key: a
-> Index Scan using t_a_c_idx on t
(6 rows)
Thanks
Richard
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