Re: Assert !bms_overlap(joinrel->relids, required_outer)
От | Richard Guo |
---|---|
Тема | Re: Assert !bms_overlap(joinrel->relids, required_outer) |
Дата | |
Msg-id | CAMbWs48NToCo3YOwGoXztbbCYOAC3Pj7dHXULK98jc54DxikYw@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Assert !bms_overlap(joinrel->relids, required_outer) (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-hackers |
On Fri, Jun 30, 2023 at 11:00 PM Tom Lane <tgl@sss.pgh.pa.us> wrote:
Richard Guo <guofenglinux@gmail.com> writes:
> I think it just makes these two assertions meaningless to skip it for
> non-nestloop joins if the input paths are for otherrels, because paths
> would never be parameterized by the member relations. So these two
> assertions would always be true for otherrel paths. I think this is why
> we have not noticed any problem by now.
After studying this some more, I think that maybe it's the "run
parameterization tests on the parent relids" bit that is misguided.
I believe the way it's really working is that all paths arriving
here are parameterized by top parents, because that's the only thing
we generate to start with. A path can only become parameterized
by an otherrel when we apply reparameterize_path_by_child to it.
But the only place that happens is in try_nestloop_path itself
(or try_partial_nestloop_path), and then we immediately wrap it in
a nestloop join node, which becomes a child of an append that's
forming a partitionwise join. The partitionwise join as a
whole won't be parameterized by any child rels. So I think that
a path that's parameterized by a child rel can't exist "in the wild"
in a way that would allow it to get fed to one of the try_xxx_path
functions. This explains why the seeming oversights in the merge
and hash cases aren't causing a problem.
If this theory is correct, we could simplify try_nestloop_path a
bit. I doubt the code savings would matter, but maybe it's
worth changing for clarity's sake.
Yeah, I think this theory is correct that all paths arriving at
try_xxx_path are parameterized by top parents. But I do not get how to
simplify try_nestloop_path on the basis of that. Would you please
elaborate on that?
Thanks
Richard
try_xxx_path are parameterized by top parents. But I do not get how to
simplify try_nestloop_path on the basis of that. Would you please
elaborate on that?
Thanks
Richard
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