Re: Have I found an interval arithmetic bug?
От | Zhihong Yu |
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Тема | Re: Have I found an interval arithmetic bug? |
Дата | |
Msg-id | CALNJ-vRF71-c8oubm96wx4qBz1TQr2Dm5ocQAYbHmtmf_gBTmg@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Have I found an interval arithmetic bug? (Isaac Morland <isaac.morland@gmail.com>) |
Ответы |
Re: Have I found an interval arithmetic bug?
|
Список | pgsql-hackers |
Hi,
The mix of interval and comparison with float is not easy to interpret. See the following (I got 0.0833 since the result for interval '0.3 years' + interval '0.4 years' - ... query was 1 month and 1/12 ~= 0.0833).
yugabyte=# select 0.3 * '1 year'::interval + 0.4 * '1 year'::interval - 0.7 * '1 year'::interval = '0.0833 year'::interval;
?column?
----------
f
?column?
----------
f
As long as Bruce's patch makes improvements over the current behavior, I think that's fine.
Cheers
On Fri, Apr 2, 2021 at 6:24 PM Isaac Morland <isaac.morland@gmail.com> wrote:
On Fri, 2 Apr 2021 at 21:08, Zhihong Yu <zyu@yugabyte.com> wrote:Hi,I got a local build with second patch where:yugabyte=# SELECT interval '0.3 years' + interval '0.4 years' -
interval '0.7 years';
?column?
----------
1 monI think the outcome is a bit unintuitive (I would expect result close to 0).That's not fundamentally different from this:odyssey=> select 12 * 3/10 + 12 * 4/10 - 12 * 7/10;?column?-----------1(1 row)odyssey=>And actually the result is pretty close to 0. I mean it’s less than 0.1 year.I wonder if it might have been better if only integers had been accepted for the components? If you want 0.3 years write 0.3 * '1 year'::interval. But changing it now would be a pretty significant backwards compatibility break.There's really no avoiding counterintuitive behaviour though. Look at this:odyssey=> select 0.3 * '1 year'::interval + 0.4 * '1 year'::interval - 0.7 * '1 year'::interval;?column?-------------------1 mons +30 days(1 row)odyssey=> select 0.3 * '1 year'::interval + 0.4 * '1 year'::interval - 0.7 * '1 year'::interval = '0';?column?----------t(1 row)odyssey=>In other words, doing the “same” calculation but with multiplying 1 year intervals by floats to get the values to add, you end up with an interval that while not identical to 0 does compare equal to 0. So very close to 0; in fact, as close to 0 as you can get without actually being identically 0.
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