Re: Have we tried to treat CTE as SubQuery in planner?
От | Andy Fan |
---|---|
Тема | Re: Have we tried to treat CTE as SubQuery in planner? |
Дата | |
Msg-id | CAKU4AWqg2zSyvnT9uf12yFRdHx9ceRV9tzHjSgqr7rs4NY9crg@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Have we tried to treat CTE as SubQuery in planner? (Tom Lane <tgl@sss.pgh.pa.us>) |
Список | pgsql-hackers |
On Sat, Nov 14, 2020 at 2:14 PM Tom Lane <tgl@sss.pgh.pa.us> wrote:
Andy Fan <zhihui.fan1213@gmail.com> writes:
> Take the following example:
> insert into cte1 select i, i from generate_series(1, 1000000)i;
> create index on cte1(a);
> explain
> with cte1 as (select * from cte1)
> select * from c where a = 1;
> It needs to do seq scan on the above format, however it is pretty
> quick if we change the query to
> select * from (select * from cte1) c where a = 1;
This example seems both confused and out of date. Since we changed
the rules on materializing CTEs (in 608b167f9), I get
Sorry, I should have tested it again on the HEAD, and 608b167f9 is exactly
the thing I mean.
regression=# create table c as select i as a, i from generate_series(1, 1000000)i;
SELECT 1000000
regression=# create index on c(a);
CREATE INDEX
regression=# explain
regression-# with cte1 as (select * from c)
regression-# select * from cte1 where a = 1;
QUERY PLAN
--------------------------------------------------------------------------
Bitmap Heap Scan on c (cost=95.17..4793.05 rows=5000 width=8)
Recheck Cond: (a = 1)
-> Bitmap Index Scan on c_a_idx (cost=0.00..93.92 rows=5000 width=0)
Index Cond: (a = 1)
(4 rows)
regards, tom lane
Best Regards
Andy Fan
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