Re: ECPG bug: PRAPARE FOR
От | David G. Johnston |
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Тема | Re: ECPG bug: PRAPARE FOR |
Дата | |
Msg-id | CAKFQuwZTmZrNDjLUo-VZxLEpQqo0Sn82-8tkOSiZ02cnLq2D3w@mail.gmail.com обсуждение исходный текст |
Ответ на | ECPG bug: PRAPARE FOR (1250kv <1250kv@gmail.com>) |
Ответы |
Re: ECPG bug: PRAPARE FOR
|
Список | pgsql-bugs |
On Tue, Oct 20, 2020 at 9:47 AM 1250kv <1250kv@gmail.com> wrote:
HelloI have code:void main()
{
char *foo = "CALL "My_Proc"(?)";
EXEC SQL char *stmt = foo;
EXEC SQL PREPARE prep_stmt FROM :stmt;
EXEC SQL char *stmt2 = "CALL \x22OMy_Proc\x22(?)";
EXEC SQL PREPARE prep_stmt2 FROM :stmt2;
EXEC SQL PREPARE prep_stmt3 FROM "CALL "My_Proc"(?)";
}ecpg --version
ecpg (PostgreSQL) 13.0 (Ubuntu 13.0-1.pgdg20.04+1)ecpg sample.pgc -o sample.csample.pgc:10: ERROR: syntax error at or near "My_Proc"
General usage questions regarding PostgreSQL and ECPG should be sent to the -general list.
I don't know the correct answer here but maybe using dollar quoting within the PostgreSQL SQL statement instead of double-quotes will help. Something like:
prepare prep_stat3 from "call $$My_Proc$$()";
Asking an actual question does help others to figure out where you are confused instead of just guessing.
David J.
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