Re: Generate a series of single days from a table of intervals.
От | David G. Johnston |
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Тема | Re: Generate a series of single days from a table of intervals. |
Дата | |
Msg-id | CAKFQuwY0O3bDbGmkvQ_V6m6L6pi_m4ZTr48VANnaXPO8yy4DvA@mail.gmail.com обсуждение исходный текст |
Ответ на | Generate a series of single days from a table of intervals. (Paul Linehan <linehanp@tcd.ie>) |
Ответы |
Re: Generate a series of single days from a table of intervals.
|
Список | pgsql-novice |
I wish to generate a series of dates
from these intervals and
also to generate the intervening dates with a status of 0 (say
See "LEFT JOIN" and "COALESCE"
The output I need is:
date_val status
2016-04-01 0
2016-04-02 1
2016-04-03 1
2016-04-04 1
2016-04-05 1
2016-04-06 0
2016-04-02 0
Typo?
..
..<status as appropriate for the rest of the month>
..
2016-04-30 0
I would like to do this using a recursive CTE if it's the best solution,
but I'm open to other approaches - different approaches appreciated.
Really? That should be the last choice of execution strategy.
This isn't a tree, I'm doubtful that a recursive CTE is needed.
CREATE TABLE testdate (datein date, dateout date, status int);
INSERT INTO testdate VALUES ('2016-04-02', '2016-04-05', 1);
INSERT INTO testdate VALUES ('2016-04-15', '2016-04-18', 1);
INSERT INTO testdate VALUES ('2016-04-25', '2016-04-30', 1);
David J.
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