Re: proposal: window function - change_number
От | Rémi Cura |
---|---|
Тема | Re: proposal: window function - change_number |
Дата | |
Msg-id | CAJvUf_smqKnqY5ZiFVS8+kuWfZhM+WqMbLVkeEYvJbS93FSqYA@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: proposal: window function - change_number (Andrew Gierth <andrew@tao11.riddles.org.uk>) |
Ответы |
Re: proposal: window function - change_number
|
Список | pgsql-hackers |
Hey, sorry I what I say is obvious for you .
If I understood your problem correctly, it is strictly equivalent to this one :
http://postgresql.1045698.n5.nabble.com/Count-of-records-in-a-row-td5775363.html
http://postgresql.1045698.n5.nabble.com/Count-of-records-in-a-row-td5775363.html
there is a postgres trick to solve this problem :
is to generate a row number by the order you want , then a row number by the group ,
2014-09-21 17:51 GMT+02:00 Andrew Gierth <andrew@tao11.riddles.org.uk>:
>>>>> "Pavel" == Pavel Stehule <pavel.stehule@gmail.com> writes:
Pavel> Hi
Pavel> I tried to solve following task:
Pavel> I have a table
Pavel> start, reason, km
Pavel> =============
Pavel> 2014-01-01 08:00:00, private, 10
Pavel> 2014-01-01 09:00:00, commerc, 20
Pavel> 2014-01-01 10:00:00, commerc, 20
Pavel> 2014-01-01 11:00:00, private, 8
Pavel> and I would reduce these rows to
Pavel> 2014-01-01 08:00:00, private, 10
Pavel> 2014-01-01 09:00:00, commerc, 20 + 20 = 40
Pavel> 2014-01-01 11:00:00, private, 8
Pavel> It is relative hard to it now with SQL only.
Only relatively. My standard solution is something like this:
select start_time, reason, sum(km) as km
from (select max(label_time) over (order by start) as start_time,
reason, km
from (select start, reason, km,
case when reason
is distinct from
lag(reason) over (order by start)
then start
end as label_time
from yourtable
) s2
) s1
group by start_time, reason
order by start_time;
(Your change_number idea is essentially equivalent to doing
sum(case when x is distinct from lag(x) over w then 1 end) over w,
except that since window functions can't be nested, that expression
requires a subquery.)
--
Andrew (irc:RhodiumToad)
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