Re: BUG #12330: ACID is broken for unique constraints
От | Merlin Moncure |
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Тема | Re: BUG #12330: ACID is broken for unique constraints |
Дата | |
Msg-id | CAHyXU0zjQAB5pNgZ3y=1wpWJtttw3g3XCPYHwCBWVgjBOuUyUw@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: BUG #12330: ACID is broken for unique constraints (Kevin Grittner <kgrittn@ymail.com>) |
Ответы |
Re: BUG #12330: ACID is broken for unique constraints
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Список | pgsql-hackers |
On Fri, Dec 26, 2014 at 12:38 PM, Kevin Grittner <kgrittn@ymail.com> wrote: > Tom Lane <tgl@sss.pgh.pa.us> wrote: > >> Just for starters, a 40XXX error report will fail to provide the >> duplicated key's value. This will be a functional regression, > > Not if, as is normally the case, the transaction is retried from > the beginning on a serialization failure. Either the code will > check for a duplicate (as in the case of the OP on this thread) and > they won't see the error, *or* the the transaction which created > the duplicate key will have committed before the start of the retry > and you will get the duplicate key error. I'm not buying that; that argument assumes duplicate key errors are always 'upsert' driven. Although OP's code may have checked for duplicates it's perfectly reasonable (and in many cases preferable) to force the transaction to fail and report the error directly back to the application. The application will then switch on the error code and decide what to do: retry for deadlock/serialization or abort for data integrity error. IOW, the error handling semantics are fundamentally different and should not be mixed. merlin
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