How to do an update with XML column ?
От | celati Laurent |
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Тема | How to do an update with XML column ? |
Дата | |
Msg-id | CAHByMH0taZ_gnh4kYYkPiOV-ZSRK-MjY=3ViMHzs4T8ddVH1MA@mail.gmail.com обсуждение исходный текст |
Ответы |
Re: How to do an update with XML column ?
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Список | pgsql-general |
Dear all,
I'm taking the liberty to ask an question. Do you know if there are some ways in order to update and/or do group by with an XML column ?
For instance,
select id, unnest(xpath( '//cit:CI_Organisation/cit:name/gco:CharacterString/text()', CAST(data AS XML), ARRAY[ ARRAY['cit', 'http://standards.iso.org/iso/19115/-3/cit/2.0'], ARRAY['gco', 'http://standards.iso.org/iso/19115/-3/gco/1.0'], ARRAY['mdb','http://standards.iso.org/iso/19115/-3/mdb/2.0'], ARRAY['cat','http://standards.iso.org/iso/19115/-3/cat/1.0'], ])) as orga_name, changedate, createdate, displayorder, doctype, extra, popularity, rating, root, schemaid, title, istemplate, isharvested, harvesturi, harvestuuid, groupowner, metadata.owner, metadata.source, uuid from public.metadata group by orga_name
I obtained :
ERROR: could not identify an equality operator for type xml
LINE 39: group by orga_name ^
SQL state: 42883
Character: 2556
Thanks so much
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